(x+1)(x^2-x+1)=0

Solution for (x+1)(x^2-x+1)=0 equation:

Simplifying
(x + 1)(x2 + -1x + 1) = 0

Reorder the terms:
(1 + x)(x2 + -1x + 1) = 0

Reorder the terms:
(1 + x)(1 + -1x + x2) = 0

Multiply (1 + x) * (1 + -1x + x2)
(1(1 + -1x + x2) + x(1 + -1x + x2)) = 0
((1 * 1 + -1x * 1 + x2 * 1) + x(1 + -1x + x2)) = 0
((1 + -1x + 1x2) + x(1 + -1x + x2)) = 0
(1 + -1x + 1x2 + (1 * x + -1x * x + x2 * x)) = 0
(1 + -1x + 1x2 + (1x + -1x2 + x3)) = 0

Reorder the terms:
(1 + -1x + 1x + 1x2 + -1x2 + x3) = 0

Combine like terms: -1x + 1x = 0
(1 + 0 + 1x2 + -1x2 + x3) = 0
(1 + 1x2 + -1x2 + x3) = 0

Combine like terms: 1x2 + -1x2 = 0
(1 + 0 + x3) = 0
(1 + x3) = 0

Solving
1 + x3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + x3 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + x3 = 0 + -1
x3 = 0 + -1

Combine like terms: 0 + -1 = -1
x3 = -1

Simplifying
x3 = -1

Reorder the terms:
1 + x3 = -1 + 1

Combine like terms: -1 + 1 = 0
1 + x3 = 0

The solution to this equation could not be determined.